Pentagram

Pentagram

Fun Facts about Pentagram

Do you know that sum of all angles of a pentagram whose all five sides are extended to meet at five points is 180^{\circ}?

For example, sum of all angles x_1, x_2, x_3, x_4 and x_5 in below figure of a pentagram is equal to 180^{\circ}.

Pentagram angles
Fig. 1 – Pentagram angles

Proof:

It is easy to prove that:

(1)   \begin{equation*} a + b = 180 + x_1 \end{equation*}

(2)   \begin{equation*} b + c = 180 + x_2 \end{equation*}

(3)   \begin{equation*} c + d = 180 + x_3 \end{equation*}

(4)   \begin{equation*} d + e = 180 + x_4 \end{equation*}

(5)   \begin{equation*} e + a = 180 + x_5 \end{equation*}

Let’s say sum of all angles from x_1 to x_5 is S. Adding all five equations (1) … (5) above, we get:

(6)   \begin{equation*} 2(a + b + c + d + e) = 900 + S \end{equation*}

We already know that sum of all interior angles of a pentagon is 540^0. So above equation (6) becomes:

    \begin{equation*} 2 * 540 = 900 + S, therefore S = 180 \end{equation*}

Generalization:

We can generalize this to any star polygon with number of vertices n greater than 4. It is:

    \begin{equation*} 360 (n - 2) = 180n + S \end{equation*}

    \begin{equation*} S = 180 (n - 4) where n > 4 \end{equation*}

As An Afterthought:

My previous article about Golden Ratio applies to pentagram also. For example, suppose \overline{ab}, \overline{ac}, \overline{bc} and \overline{ad} are lengths of line segments connecting points a-b, a-c, b-c and a-d respectively in Figure 2 shown below.

Golden Ratio in Pentagram
Figure 2 – Golden Ratio in Pentagram

Then

    \begin{equation*} \frac{\overline{ad}}{\overline{ac}} \approx 1.618 ... \end{equation*}

    \begin{equation*} \frac{\overline{ac}}{\overline{ab}} \approx 1.618 ... \end{equation*}

    \begin{equation*} \frac{\overline{ab}}{\overline{bc}} \approx 1.618 ... \end{equation*}

I hope you enjoyed reading this article. Please leave comments if you have any suggestions.

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